designoir
getAge
The calculation of an age (given a date of birth) isn’t a trivial task in a PHP world. Although I guess hope that there are PHP coders who are up to such a job, it seems that they are rather shy. In any case, my search resulted in nothing but amazingly inaccurate, wrong and/or long winded solutions. It’s about time that somebody saves our honor and … alright, I’ll do it.
getAge.php
The function takes a year, month and day of birth as single arguments in the said order. It returns full years.
<?php
/**
* function getAge
* Copyright (C) 2006 Dao Gottwald
*
* This library is free software; you can redistribute it and/or
* modify it under the terms of the GNU Lesser General Public
* License as published by the Free Software Foundation; either
* version 2.1 of the License, or (at your option) any later version.
*
* This library is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
* Lesser General Public License for more details.
*
* You should have received a copy of the GNU Lesser General Public
* License along with this library; if not, write to the Free Software
* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
*
* Contact information:
* Dao Gottwald <dao at design-noir.de>
*
* @version 1.0
*/
function getAge($y, $m, $d) {
return date('Y') - $y - (date('n') < (ltrim($m,'0') + (date('j') < ltrim($d,'0'))));
}
?>
That’s it? – Yep, that’s it. It wasn’t so bad, was it?
Example #1: test-cases.php
Now some test cases, let’s hope it works.
<?php
require_once 'getAge.php';
function test($y, $m, $d) {
echo str_pad($y.'-'.$m.'-'.$d, 12), getAge($y, $m, $d), "\n";
}
test(1985, 10, 27);
test(2000, 1, 1);
test('2000', '01', '01');
test(2000, 12, 31);
test(2000, date('m'), 1);
test(2000, date('m'), date('d'));
test(2000, date('m', strtotime('+1 day')), date('d', strtotime('+1 day')));
test(-38000, 1, 1);
test(2100, 1, 1);
test(2100, 12, 31);
echo "\n";
for ($i = 0; $i <= 30; $i += 3) {
$t = strtotime('-'.$i.'00 days');
test(date('Y', $t), date('m', $t), date('d', $t));
}
?>
Comments
-
dooof wrote on March 29, 2006 07:25 AM BST ():
dooooooooooooof
-
Gerd wrote on November 22, 2006 02:09 AM GMT ():
Sieht alles ganz gut aus, aber was ist mit den Jahren vor 1582 (julianische Kalender)?
-
Dao wrote on November 22, 2006 02:50 AM GMT ():
Wer am 4. Oktober 1582 (julianisch) geboren ist, würde auch nach dem gregorianischen Kalender am 4. Oktober feiern, nicht? Ist ja nicht so, dass wir von Jahrestag zu Jahrestag die Tage oder Sekunden zählen – nein, wir interessieren uns nur fürs Datum. Und um mehr als die alltägliche Altersangabe geht es hier nicht (deshalb auch bewusst nur ganzzahlige Ergebnisse).
-
justSomeGuy wrote on April 10, 2007 11:21 PM BST ():
Wow mate nice one, i also found some long ways to do it but was looking for a short way thanks a bunch
-
Nathan Salter wrote on August 22, 2008 04:48 PM BST ():
You should really put in the checkdate() function to avoid people typing in invalid dates, and also put a function that makes sure the date isn’t in the future. You could use a strpos() function to check that as well, check their date with the current date. I know it won’t look so elegant, but would work slightly more efficiently
-
Martin wrote on July 13, 2009 08:54 AM BST ():
Ich habe ewig nach einer guten Altersberechnung gesucht.
Danke dafür :)
